ampage Tube Amps / Music Electronics 
For current discussions, please visit Music Electronics Forum. 
4/21/2003 9:25 PM  
Dr. Blues 
balancing resistors here's a question for the cognoscenti. i want to use 2 series 180uf @ 400Vcaps in series for the first caps in a power supply filter. the voltage off the rectifier is 600V. according to the cornell dubilier site, (see page 13, http://www.cornelldubilier.com/appguide.pdf ) this equation is used to calculate balancing resistors: For 2 capacitors in series: R = (2Vr  Vb) / (0.0015 C Vb) For n > 2 capacitors: R = (Vr  Vb/n) / (0.00075 C Vb) where R = resistance in Megohms Vr = max rated surge voltage Vb = max voltage across entire bank of caps n = number of caps in series C = capacitance in uF using this formula the resistors should be 1.2M. i don't recall seeing any circuits using such high balancing resistors. usually they're 220k. e.g., the aa270 super reverb uses two 70uf @ 350V and two 220k balancing resistors. with a standby voltage of 510V, by the formula above the balancing resistors for the aa270 should be 3.5M. is there another formula to calculate the balancing resistor value? should i use the calculated value or go with convention? ciao...dr. blues 

Today  
ampage archive  And now, a word from our sponsors:


4/21/2003 9:54 PM  
R.G.  That formula is intended to tell you the *maximum* resistance you should use to let the resistors swamp the internal leakages well enough. It's perfectly permissible to go lower than that. I tend to approach it from the other way. Bleeder resistors are a good thing for a hacker to use. The smaller the resistor value (that is, the more current the resistors draw) the sooner the caps have run down to a safe voltage level when you turn the switch off. So I tend to say "how much static bleeder resistor power can I stand in there?" and put in something that dissipates about that much. Practical values are about a watt. So for a cap with 300V across it, the resistor would be (300**2)/1W = 90K. So if I put in a 100K 3W power resistor across each one, and I'm done. Doubling the resistance cuts the power in half, so a 200K resistor would be about half a watt, and you could use a 1W resistor, or two half watt resistors in series or parallel to get the same value. Anything between 100K or so up to the value the formula gives you will do a fine job of equalizing the voltage across the caps. R.G. 

4/22/2003 4:45 PM  
Dr. Blues 
R.G., thanx for the response. very helpful. ciao...dr. blues 

Page 1 of 1 